What is the correct form of the main function in C if i expect command line arguments?

Is it like this?


int main(int argc, char *argv[])


And if the first argument represents the filename (and location), then argc counts all arguments, or just those except the first one. In other words, a program with no extra arguments would have argc==1?

What is the correct form of the main function in C if i expect command line arguments?
You have two synthaxes :


1) int main(int argc, char *argv[]);


and


2) int main(int argc, char **argv);





When a program starts, the arguments to main will have been initialized to meet the following conditions:





- argc is greater than zero.


- argv[argc] is a null pointer.


- argv[0] through to argv[argc-1] are pointers to strings whose meaning will be determined by the program.


- argv[0] will be a string containing the program's name or a null string if that is not available. Remaining elements of argv represent the arguments supplied to the program. In cases where there is only support for single-case characters, the contents of these strings will be supplied to the program in lower-case.





To illustrate these points, here is a simple program which writes the arguments supplied to main on the program's standard output.





#include %26lt;stdio.h%26gt;


#include %26lt;stdlib.h%26gt;





int main(int argc, char **argv)


{


while(argc--)


printf("%s\n", *argv++);


exit(EXIT_SUCCESS);


}
Reply:yes, a program with no extra argu have argc==1.